%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SYO202^5 : TPTP v9.2.0. Released v4.0.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n006.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 08:08:44 PM UTC 2025 % Result : Theorem 4.74s 4.96s % Output : Proof 4.74s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.00/0.08 % Problem : SYO202^5 : TPTP v9.2.0. Released v4.0.0. % 0.00/0.09 % Command : duper %s % 0.08/0.29 % Computer : n006.cluster.edu % 0.08/0.29 % Model : x86_64 x86_64 % 0.08/0.29 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.08/0.29 % Memory : 8042.1875MB % 0.08/0.29 % OS : Linux 3.10.0-693.el7.x86_64 % 0.13/0.29 % CPULimit : 300 % 0.13/0.29 % WCLimit : 300 % 0.13/0.29 % DateTime : Fri Oct 3 12:53:08 EDT 2025 % 0.13/0.29 % CPUTime : % 4.74/4.96 SZS status Theorem for theBenchmark.p % 4.74/4.96 SZS output start Proof for theBenchmark.p % 4.74/4.96 Clause #0 (by assumption #[]): Eq (Not (Not (Exists fun Xp => And (Xp (Eq Xp Xp)) (Not (Xp (Eq Xp Xp)))))) True % 4.74/4.96 Clause #1 (by clausification #[0]): Eq (Not (Exists fun Xp => And (Xp (Eq Xp Xp)) (Not (Xp (Eq Xp Xp))))) False % 4.74/4.96 Clause #2 (by clausification #[1]): Eq (Exists fun Xp => And (Xp (Eq Xp Xp)) (Not (Xp (Eq Xp Xp)))) True % 4.74/4.96 Clause #3 (by clausification #[2]): ∀ (a : Prop → Prop), % 4.74/4.96 Eq (And (skS.0 0 a (Eq (skS.0 0 a) (skS.0 0 a))) (Not (skS.0 0 a (Eq (skS.0 0 a) (skS.0 0 a))))) True % 4.74/4.96 Clause #4 (by clausification #[3]): ∀ (a : Prop → Prop), Eq (Not (skS.0 0 a (Eq (skS.0 0 a) (skS.0 0 a)))) True % 4.74/4.96 Clause #5 (by clausification #[3]): ∀ (a : Prop → Prop), Eq (skS.0 0 a (Eq (skS.0 0 a) (skS.0 0 a))) True % 4.74/4.96 Clause #6 (by clausification #[4]): ∀ (a : Prop → Prop), Eq (skS.0 0 a (Eq (skS.0 0 a) (skS.0 0 a))) False % 4.74/4.96 Clause #7 (by bool simp #[6]): ∀ (a : Prop → Prop), Eq (skS.0 0 a True) False % 4.74/4.96 Clause #8 (by bool simp #[5]): ∀ (a : Prop → Prop), Eq (skS.0 0 a True) True % 4.74/4.96 Clause #9 (by superposition #[8, 7]): Eq True False % 4.74/4.96 Clause #10 (by clausification #[9]): False % 4.74/4.96 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------