%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : SYO291^5 : TPTP v7.5.0. Released v4.0.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % Computer : n011.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 0s % DateTime : Tue Mar 29 00:51:05 EDT 2022 % Result : Theorem 0.51s 0.66s % Output : Proof 0.51s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.04/0.12 % Problem : SYO291^5 : TPTP v7.5.0. Released v4.0.0. % 0.04/0.12 % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % 0.13/0.33 % Computer : n011.cluster.edu % 0.13/0.33 % Model : x86_64 x86_64 % 0.13/0.33 % CPUModel : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.13/0.33 % RAMPerCPU : 8042.1875MB % 0.13/0.33 % OS : Linux 3.10.0-693.el7.x86_64 % 0.13/0.33 % CPULimit : 300 % 0.13/0.33 % DateTime : Sat Mar 12 01:07:40 EST 2022 % 0.13/0.33 % CPUTime : % 0.13/0.34 ModuleCmd_Load.c(213):ERROR:105: Unable to locate a modulefile for 'python/python27' % 0.13/0.35 Python 2.7.5 % 0.51/0.66 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/'] % 0.51/0.66 FOF formula (<kernel.Constant object at 0x1ad8d40>, <kernel.Constant object at 0x1ad84d0>) of role type named y % 0.51/0.66 Using role type % 0.51/0.66 Declaring y:fofType % 0.51/0.66 FOF formula (<kernel.Constant object at 0x1ad8758>, <kernel.DependentProduct object at 0x2ba508f79b00>) of role type named cQ % 0.51/0.66 Using role type % 0.51/0.66 Declaring cQ:(fofType->Prop) % 0.51/0.66 FOF formula (<kernel.Constant object at 0x1ad84d0>, <kernel.Single object at 0x1ad8d40>) of role type named x % 0.51/0.66 Using role type % 0.51/0.66 Declaring x:fofType % 0.51/0.66 FOF formula (<kernel.Constant object at 0x1ad8cf8>, <kernel.DependentProduct object at 0x2ba508f79998>) of role type named f % 0.51/0.66 Using role type % 0.51/0.66 Declaring f:(fofType->fofType) % 0.51/0.66 FOF formula (<kernel.Constant object at 0x1adcef0>, <kernel.DependentProduct object at 0x2ba508f79c68>) of role type named cR % 0.51/0.66 Using role type % 0.51/0.66 Declaring cR:(fofType->Prop) % 0.51/0.66 FOF formula ((forall (Xp:(fofType->Prop)), (Xp y))->((and ((and (cR x)) (cR (f x)))) (cQ y))) of role conjecture named cTEST3 % 0.51/0.66 Conjecture to prove = ((forall (Xp:(fofType->Prop)), (Xp y))->((and ((and (cR x)) (cR (f x)))) (cQ y))):Prop % 0.51/0.66 We need to prove ['((forall (Xp:(fofType->Prop)), (Xp y))->((and ((and (cR x)) (cR (f x)))) (cQ y)))'] % 0.51/0.66 Parameter fofType:Type. % 0.51/0.66 Parameter y:fofType. % 0.51/0.66 Parameter cQ:(fofType->Prop). % 0.51/0.66 Parameter x:fofType. % 0.51/0.66 Parameter f:(fofType->fofType). % 0.51/0.66 Parameter cR:(fofType->Prop). % 0.51/0.66 Trying to prove ((forall (Xp:(fofType->Prop)), (Xp y))->((and ((and (cR x)) (cR (f x)))) (cQ y))) % 0.51/0.66 Found x00:=(x0 (fun (x1:fofType)=> ((and ((and (cR x)) (cR (f x)))) (cQ x1)))):((and ((and (cR x)) (cR (f x)))) (cQ y)) % 0.51/0.66 Found (x0 (fun (x1:fofType)=> ((and ((and (cR x)) (cR (f x)))) (cQ x1)))) as proof of ((and ((and (cR x)) (cR (f x)))) (cQ y)) % 0.51/0.66 Found (fun (x0:(forall (Xp:(fofType->Prop)), (Xp y)))=> (x0 (fun (x1:fofType)=> ((and ((and (cR x)) (cR (f x)))) (cQ x1))))) as proof of ((and ((and (cR x)) (cR (f x)))) (cQ y)) % 0.51/0.66 Found (fun (x0:(forall (Xp:(fofType->Prop)), (Xp y)))=> (x0 (fun (x1:fofType)=> ((and ((and (cR x)) (cR (f x)))) (cQ x1))))) as proof of ((forall (Xp:(fofType->Prop)), (Xp y))->((and ((and (cR x)) (cR (f x)))) (cQ y))) % 0.51/0.66 Got proof (fun (x0:(forall (Xp:(fofType->Prop)), (Xp y)))=> (x0 (fun (x1:fofType)=> ((and ((and (cR x)) (cR (f x)))) (cQ x1))))) % 0.51/0.66 Time elapsed = 0.038047s % 0.51/0.66 node=2 cost=-94.000000 depth=2 % 0.51/0.66 :::::::::::::::::::::: % 0.51/0.66 % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.51/0.66 % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.51/0.66 (fun (x0:(forall (Xp:(fofType->Prop)), (Xp y)))=> (x0 (fun (x1:fofType)=> ((and ((and (cR x)) (cR (f x)))) (cQ x1))))) % 0.51/0.66 % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p %------------------------------------------------------------------------------