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cocATP---0.2.0.THM-Prf.s

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%------------------------------------------------------------------------------
% File     : cocATP---0.2.0
% Problem  : SYO306^5 : TPTP v7.5.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p

% Computer : n022.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Tue Mar 29 00:51:08 EDT 2022

% Result   : Theorem 0.51s 0.72s
% Output   : Proof 0.51s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.11  % Problem    : SYO306^5 : TPTP v7.5.0. Released v4.0.0.
% 0.03/0.11  % Command    : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.11/0.32  % Computer   : n022.cluster.edu
% 0.11/0.32  % Model      : x86_64 x86_64
% 0.11/0.32  % CPUModel   : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.11/0.32  % RAMPerCPU  : 8042.1875MB
% 0.11/0.32  % OS         : Linux 3.10.0-693.el7.x86_64
% 0.11/0.32  % CPULimit   : 300
% 0.11/0.32  % DateTime   : Sat Mar 12 02:30:57 EST 2022
% 0.11/0.32  % CPUTime    : 
% 0.11/0.33  ModuleCmd_Load.c(213):ERROR:105: Unable to locate a modulefile for 'python/python27'
% 0.11/0.33  Python 2.7.5
% 0.51/0.72  Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/']
% 0.51/0.72  FOF formula (<kernel.Constant object at 0x253a488>, <kernel.DependentProduct object at 0x2b735b6875f0>) of role type named cT
% 0.51/0.72  Using role type
% 0.51/0.72  Declaring cT:(fofType->Prop)
% 0.51/0.72  FOF formula (<kernel.Constant object at 0x253a0e0>, <kernel.DependentProduct object at 0x2b735b687d40>) of role type named cS
% 0.51/0.72  Using role type
% 0.51/0.72  Declaring cS:(fofType->Prop)
% 0.51/0.72  FOF formula ((forall (P:(fofType->Prop)), ((forall (Xx:fofType), (P Xx))->(forall (Xx:fofType), (P Xx))))->((forall (Xx:fofType), ((and (cS Xx)) (cT Xx)))->(forall (Xx:fofType), ((and (cS Xx)) (cT Xx))))) of role conjecture named cDUP_BUG_2
% 0.51/0.72  Conjecture to prove = ((forall (P:(fofType->Prop)), ((forall (Xx:fofType), (P Xx))->(forall (Xx:fofType), (P Xx))))->((forall (Xx:fofType), ((and (cS Xx)) (cT Xx)))->(forall (Xx:fofType), ((and (cS Xx)) (cT Xx))))):Prop
% 0.51/0.72  Parameter fofType_DUMMY:fofType.
% 0.51/0.72  We need to prove ['((forall (P:(fofType->Prop)), ((forall (Xx:fofType), (P Xx))->(forall (Xx:fofType), (P Xx))))->((forall (Xx:fofType), ((and (cS Xx)) (cT Xx)))->(forall (Xx:fofType), ((and (cS Xx)) (cT Xx)))))']
% 0.51/0.72  Parameter fofType:Type.
% 0.51/0.72  Parameter cT:(fofType->Prop).
% 0.51/0.72  Parameter cS:(fofType->Prop).
% 0.51/0.72  Trying to prove ((forall (P:(fofType->Prop)), ((forall (Xx:fofType), (P Xx))->(forall (Xx:fofType), (P Xx))))->((forall (Xx:fofType), ((and (cS Xx)) (cT Xx)))->(forall (Xx:fofType), ((and (cS Xx)) (cT Xx)))))
% 0.51/0.72  Found x0:=(x (fun (x1:fofType)=> ((and (cS x1)) (cT x1)))):((forall (Xx:fofType), ((and (cS Xx)) (cT Xx)))->(forall (Xx:fofType), ((and (cS Xx)) (cT Xx))))
% 0.51/0.72  Found (x (fun (x1:fofType)=> ((and (cS x1)) (cT x1)))) as proof of ((forall (Xx:fofType), ((and (cS Xx)) (cT Xx)))->(forall (Xx:fofType), ((and (cS Xx)) (cT Xx))))
% 0.51/0.72  Found (fun (x:(forall (P:(fofType->Prop)), ((forall (Xx:fofType), (P Xx))->(forall (Xx:fofType), (P Xx)))))=> (x (fun (x1:fofType)=> ((and (cS x1)) (cT x1))))) as proof of ((forall (Xx:fofType), ((and (cS Xx)) (cT Xx)))->(forall (Xx:fofType), ((and (cS Xx)) (cT Xx))))
% 0.51/0.72  Found (fun (x:(forall (P:(fofType->Prop)), ((forall (Xx:fofType), (P Xx))->(forall (Xx:fofType), (P Xx)))))=> (x (fun (x1:fofType)=> ((and (cS x1)) (cT x1))))) as proof of ((forall (P:(fofType->Prop)), ((forall (Xx:fofType), (P Xx))->(forall (Xx:fofType), (P Xx))))->((forall (Xx:fofType), ((and (cS Xx)) (cT Xx)))->(forall (Xx:fofType), ((and (cS Xx)) (cT Xx)))))
% 0.51/0.72  Got proof (fun (x:(forall (P:(fofType->Prop)), ((forall (Xx:fofType), (P Xx))->(forall (Xx:fofType), (P Xx)))))=> (x (fun (x1:fofType)=> ((and (cS x1)) (cT x1)))))
% 0.51/0.72  Time elapsed = 0.051696s
% 0.51/0.72  node=3 cost=-94.000000 depth=2
% 0.51/0.72  ::::::::::::::::::::::
% 0.51/0.72  % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.51/0.72  % SZS output start Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.51/0.72  (fun (x:(forall (P:(fofType->Prop)), ((forall (Xx:fofType), (P Xx))->(forall (Xx:fofType), (P Xx)))))=> (x (fun (x1:fofType)=> ((and (cS x1)) (cT x1)))))
% 0.51/0.72  % SZS output end Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
%------------------------------------------------------------------------------