%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SYO345^5 : TPTP v9.2.0. Released v4.0.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n019.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 08:08:54 PM UTC 2025 % Result : Theorem 3.54s 3.72s % Output : Proof 3.54s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.11/0.12 % Problem : SYO345^5 : TPTP v9.2.0. Released v4.0.0. % 0.11/0.13 % Command : duper %s % 0.13/0.34 % Computer : n019.cluster.edu % 0.13/0.34 % Model : x86_64 x86_64 % 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.13/0.34 % Memory : 8042.1875MB % 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64 % 0.13/0.34 % CPULimit : 300 % 0.13/0.34 % WCLimit : 300 % 0.13/0.34 % DateTime : Fri Oct 3 13:22:53 EDT 2025 % 0.13/0.34 % CPUTime : % 3.54/3.72 SZS status Theorem for theBenchmark.p % 3.54/3.72 SZS output start Proof for theBenchmark.p % 3.54/3.72 Clause #0 (by assumption #[]): Eq (Not (Eq (cH (Eq (cH True) (cH False))) (cH False))) True % 3.54/3.72 Clause #1 (by clausification #[0]): Eq (Eq (cH (Eq (cH True) (cH False))) (cH False)) False % 3.54/3.72 Clause #2 (by clausification #[1]): Ne (cH (Eq (cH True) (cH False))) (cH False) % 3.54/3.72 Clause #3 (by identity loobHoist #[2]): Or (Ne (cH True) (cH False)) (Eq (Eq (cH True) (cH False)) False) % 3.54/3.72 Clause #4 (by identity boolHoist #[2]): Or (Ne (cH False) (cH False)) (Eq (Eq (cH True) (cH False)) True) % 3.54/3.72 Clause #5 (by clausification #[3]): Or (Ne (cH True) (cH False)) (Ne (cH True) (cH False)) % 3.54/3.72 Clause #6 (by eliminate duplicate literals #[5]): Ne (cH True) (cH False) % 3.54/3.72 Clause #7 (by clausification #[4]): Or (Ne (cH False) (cH False)) (Eq (cH True) (cH False)) % 3.54/3.72 Clause #8 (by eliminate resolved literals #[7]): Eq (cH True) (cH False) % 3.54/3.72 Clause #9 (by forward contextual literal cutting #[8, 6]): False % 3.54/3.72 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------