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cocATP---0.2.0.THM-Prf.s

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%------------------------------------------------------------------------------
% File     : cocATP---0.2.0
% Problem  : SYO352^5 : TPTP v7.5.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p

% Computer : n023.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Tue Mar 29 00:51:13 EDT 2022

% Result   : Theorem 0.49s 0.69s
% Output   : Proof 0.49s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.11  % Problem    : SYO352^5 : TPTP v7.5.0. Released v4.0.0.
% 0.04/0.12  % Command    : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.12/0.33  % Computer   : n023.cluster.edu
% 0.12/0.33  % Model      : x86_64 x86_64
% 0.12/0.33  % CPUModel   : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % RAMPerCPU  : 8042.1875MB
% 0.12/0.33  % OS         : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit   : 300
% 0.12/0.33  % DateTime   : Sat Mar 12 06:41:56 EST 2022
% 0.12/0.33  % CPUTime    : 
% 0.12/0.34  ModuleCmd_Load.c(213):ERROR:105: Unable to locate a modulefile for 'python/python27'
% 0.12/0.34  Python 2.7.5
% 0.49/0.69  Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/']
% 0.49/0.69  FOF formula (<kernel.Constant object at 0x1624ab8>, <kernel.DependentProduct object at 0x1624d88>) of role type named n
% 0.49/0.69  Using role type
% 0.49/0.69  Declaring n:(fofType->fofType)
% 0.49/0.69  FOF formula (<kernel.Constant object at 0x1624a70>, <kernel.DependentProduct object at 0x18dfc68>) of role type named m
% 0.49/0.69  Using role type
% 0.49/0.69  Declaring m:(fofType->fofType)
% 0.49/0.69  FOF formula ((forall (X:fofType) (P:(fofType->Prop)), ((P (m X))->(P (n X))))->(forall (Q:((fofType->fofType)->Prop)), ((Q m)->(Q n)))) of role conjecture named cE5EXT
% 0.49/0.69  Conjecture to prove = ((forall (X:fofType) (P:(fofType->Prop)), ((P (m X))->(P (n X))))->(forall (Q:((fofType->fofType)->Prop)), ((Q m)->(Q n)))):Prop
% 0.49/0.69  Parameter fofType_DUMMY:fofType.
% 0.49/0.69  We need to prove ['((forall (X:fofType) (P:(fofType->Prop)), ((P (m X))->(P (n X))))->(forall (Q:((fofType->fofType)->Prop)), ((Q m)->(Q n))))']
% 0.49/0.69  Parameter fofType:Type.
% 0.49/0.69  Parameter n:(fofType->fofType).
% 0.49/0.69  Parameter m:(fofType->fofType).
% 0.49/0.69  Trying to prove ((forall (X:fofType) (P:(fofType->Prop)), ((P (m X))->(P (n X))))->(forall (Q:((fofType->fofType)->Prop)), ((Q m)->(Q n))))
% 0.49/0.69  Found functional_extensionality_dep0000:=(functional_extensionality_dep000 n):((forall (x:fofType), (((eq fofType) (m x)) (n x)))->(((eq (fofType->fofType)) m) n))
% 0.49/0.69  Found (functional_extensionality_dep000 n) as proof of ((forall (X:fofType), (((eq fofType) (m X)) (n X)))->(((eq (fofType->fofType)) m) n))
% 0.49/0.69  Found ((functional_extensionality_dep00 m) n) as proof of ((forall (X:fofType), (((eq fofType) (m X)) (n X)))->(((eq (fofType->fofType)) m) n))
% 0.49/0.69  Found (((functional_extensionality_dep0 (fun (x1:fofType)=> fofType)) m) n) as proof of ((forall (X:fofType), (((eq fofType) (m X)) (n X)))->(((eq (fofType->fofType)) m) n))
% 0.49/0.69  Found ((((functional_extensionality_dep fofType) (fun (x1:fofType)=> fofType)) m) n) as proof of ((forall (X:fofType), (((eq fofType) (m X)) (n X)))->(((eq (fofType->fofType)) m) n))
% 0.49/0.69  Found ((((functional_extensionality_dep fofType) (fun (x1:fofType)=> fofType)) m) n) as proof of ((forall (X:fofType), (((eq fofType) (m X)) (n X)))->(((eq (fofType->fofType)) m) n))
% 0.49/0.69  Found ((((functional_extensionality_dep fofType) (fun (x1:fofType)=> fofType)) m) n) as proof of ((forall (X:fofType) (P:(fofType->Prop)), ((P (m X))->(P (n X))))->(forall (Q:((fofType->fofType)->Prop)), ((Q m)->(Q n))))
% 0.49/0.69  Got proof ((((functional_extensionality_dep fofType) (fun (x1:fofType)=> fofType)) m) n)
% 0.49/0.69  Time elapsed = 0.073417s
% 0.49/0.69  node=11 cost=-290.000000 depth=5
% 0.49/0.69  ::::::::::::::::::::::
% 0.49/0.69  % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.49/0.69  % SZS output start Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.49/0.69  ((((functional_extensionality_dep fofType) (fun (x1:fofType)=> fofType)) m) n)
% 0.49/0.69  % SZS output end Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
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