%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : SYO353^5 : TPTP v7.5.0. Released v4.0.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % Computer : n032.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 0s % DateTime : Tue Mar 29 00:51:14 EDT 2022 % Result : Theorem 0.35s 0.51s % Output : Proof 0.35s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.00/0.08 % Problem : SYO353^5 : TPTP v7.5.0. Released v4.0.0. % 0.00/0.08 % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % 0.08/0.27 % Computer : n032.cluster.edu % 0.08/0.27 % Model : x86_64 x86_64 % 0.08/0.27 % CPUModel : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.08/0.27 % RAMPerCPU : 8042.1875MB % 0.08/0.27 % OS : Linux 3.10.0-693.el7.x86_64 % 0.08/0.27 % CPULimit : 300 % 0.08/0.27 % DateTime : Sat Mar 12 06:19:47 EST 2022 % 0.08/0.27 % CPUTime : % 0.08/0.28 ModuleCmd_Load.c(213):ERROR:105: Unable to locate a modulefile for 'python/python27' % 0.08/0.28 Python 2.7.5 % 0.35/0.51 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/'] % 0.35/0.51 FOF formula (<kernel.Constant object at 0xc42e60>, <kernel.Type object at 0xc42ea8>) of role type named a_type % 0.35/0.51 Using role type % 0.35/0.51 Declaring a:Type % 0.35/0.51 FOF formula (<kernel.Constant object at 0xc42d40>, <kernel.Constant object at 0xc42c68>) of role type named v % 0.35/0.51 Using role type % 0.35/0.51 Declaring v:a % 0.35/0.51 FOF formula (<kernel.Constant object at 0xc4b5a8>, <kernel.Constant object at 0xc42c68>) of role type named u % 0.35/0.51 Using role type % 0.35/0.51 Declaring u:a % 0.35/0.51 FOF formula ((forall (Xq:(a->Prop)), ((Xq u)->(Xq v)))->(forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) v)))) of role conjecture named cE1LEIBEQ1_pme % 0.35/0.51 Conjecture to prove = ((forall (Xq:(a->Prop)), ((Xq u)->(Xq v)))->(forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) v)))):Prop % 0.35/0.51 We need to prove ['((forall (Xq:(a->Prop)), ((Xq u)->(Xq v)))->(forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) v))))'] % 0.35/0.51 Parameter a:Type. % 0.35/0.51 Parameter v:a. % 0.35/0.51 Parameter u:a. % 0.35/0.51 Trying to prove ((forall (Xq:(a->Prop)), ((Xq u)->(Xq v)))->(forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) v)))) % 0.35/0.51 Found x000:=(x00 u):((Q u) u) % 0.35/0.51 Found (x00 u) as proof of ((Q u) u) % 0.35/0.51 Found (fun (x00:(forall (Z:a), ((Q Z) Z)))=> (x00 u)) as proof of ((Q u) u) % 0.35/0.51 Found (fun (Q:(a->(a->Prop))) (x00:(forall (Z:a), ((Q Z) Z)))=> (x00 u)) as proof of ((forall (Z:a), ((Q Z) Z))->((Q u) u)) % 0.35/0.51 Found (fun (Q:(a->(a->Prop))) (x00:(forall (Z:a), ((Q Z) Z)))=> (x00 u)) as proof of (forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) u))) % 0.35/0.51 Found (x0 (fun (Q:(a->(a->Prop))) (x00:(forall (Z:a), ((Q Z) Z)))=> (x00 u))) as proof of (forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) v))) % 0.35/0.51 Found ((x (fun (x1:a)=> (forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) x1))))) (fun (Q:(a->(a->Prop))) (x00:(forall (Z:a), ((Q Z) Z)))=> (x00 u))) as proof of (forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) v))) % 0.35/0.51 Found (fun (x:(forall (Xq:(a->Prop)), ((Xq u)->(Xq v))))=> ((x (fun (x1:a)=> (forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) x1))))) (fun (Q:(a->(a->Prop))) (x00:(forall (Z:a), ((Q Z) Z)))=> (x00 u)))) as proof of (forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) v))) % 0.35/0.51 Found (fun (x:(forall (Xq:(a->Prop)), ((Xq u)->(Xq v))))=> ((x (fun (x1:a)=> (forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) x1))))) (fun (Q:(a->(a->Prop))) (x00:(forall (Z:a), ((Q Z) Z)))=> (x00 u)))) as proof of ((forall (Xq:(a->Prop)), ((Xq u)->(Xq v)))->(forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) v)))) % 0.35/0.51 Got proof (fun (x:(forall (Xq:(a->Prop)), ((Xq u)->(Xq v))))=> ((x (fun (x1:a)=> (forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) x1))))) (fun (Q:(a->(a->Prop))) (x00:(forall (Z:a), ((Q Z) Z)))=> (x00 u)))) % 0.35/0.51 Time elapsed = 0.046443s % 0.35/0.51 node=17 cost=-48.000000 depth=7 % 0.35/0.51 :::::::::::::::::::::: % 0.35/0.51 % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.35/0.51 % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.35/0.51 (fun (x:(forall (Xq:(a->Prop)), ((Xq u)->(Xq v))))=> ((x (fun (x1:a)=> (forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) x1))))) (fun (Q:(a->(a->Prop))) (x00:(forall (Z:a), ((Q Z) Z)))=> (x00 u)))) % 0.35/0.51 % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p %------------------------------------------------------------------------------