%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SYO367^5 : TPTP v9.2.0. Released v4.0.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n029.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 08:08:56 PM UTC 2025 % Result : Theorem 3.49s 3.67s % Output : Proof 3.49s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.03/0.12 % Problem : SYO367^5 : TPTP v9.2.0. Released v4.0.0. % 0.12/0.13 % Command : duper %s % 0.13/0.34 % Computer : n029.cluster.edu % 0.13/0.34 % Model : x86_64 x86_64 % 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.13/0.34 % Memory : 8042.1875MB % 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64 % 0.13/0.34 % CPULimit : 300 % 0.13/0.34 % WCLimit : 300 % 0.13/0.34 % DateTime : Fri Oct 3 13:36:53 EDT 2025 % 0.13/0.34 % CPUTime : % 3.49/3.67 SZS status Theorem for theBenchmark.p % 3.49/3.67 SZS output start Proof for theBenchmark.p % 3.49/3.67 Clause #0 (by assumption #[]): Eq (Not (cC cA → cC (Not (Not cA)))) True % 3.49/3.67 Clause #1 (by clausification #[0]): Eq (cC cA → cC (Not (Not cA))) False % 3.49/3.67 Clause #2 (by clausification #[1]): Eq (cC cA) True % 3.49/3.67 Clause #3 (by clausification #[1]): Eq (cC (Not (Not cA))) False % 3.49/3.67 Clause #4 (by identity loobHoist #[2]): Or (Eq (cC True) True) (Eq cA False) % 3.49/3.67 Clause #5 (by identity boolHoist #[2]): Or (Eq (cC False) True) (Eq cA True) % 3.49/3.67 Clause #6 (by bool simp #[3]): Eq (cC cA) False % 3.49/3.67 Clause #7 (by identity loobHoist #[6]): Or (Eq (cC True) False) (Eq cA False) % 3.49/3.67 Clause #8 (by identity boolHoist #[6]): Or (Eq (cC False) False) (Eq cA True) % 3.49/3.67 Clause #9 (by superposition #[8, 5]): Or (Eq cA True) (Or (Eq False True) (Eq cA True)) % 3.49/3.67 Clause #10 (by clausification #[9]): Or (Eq cA True) (Eq cA True) % 3.49/3.67 Clause #11 (by eliminate duplicate literals #[10]): Eq cA True % 3.49/3.67 Clause #12 (by backward demodulation #[11, 4]): Or (Eq (cC True) True) (Eq True False) % 3.49/3.67 Clause #14 (by backward demodulation #[11, 7]): Or (Eq (cC True) False) (Eq True False) % 3.49/3.67 Clause #16 (by clausification #[12]): Eq (cC True) True % 3.49/3.67 Clause #17 (by clausification #[14]): Eq (cC True) False % 3.49/3.67 Clause #18 (by superposition #[17, 16]): Eq False True % 3.49/3.67 Clause #19 (by clausification #[18]): False % 3.49/3.67 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------