%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SYO368^5 : TPTP v9.2.0. Released v4.0.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n003.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 08:08:57 PM UTC 2025 % Result : Theorem 4.30s 4.50s % Output : Proof 4.30s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.12/0.13 % Problem : SYO368^5 : TPTP v9.2.0. Released v4.0.0. % 0.12/0.14 % Command : duper %s % 0.13/0.34 % Computer : n003.cluster.edu % 0.13/0.34 % Model : x86_64 x86_64 % 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.13/0.34 % Memory : 8042.1875MB % 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64 % 0.13/0.34 % CPULimit : 300 % 0.13/0.34 % WCLimit : 300 % 0.13/0.34 % DateTime : Fri Oct 3 13:39:38 EDT 2025 % 0.18/0.35 % CPUTime : % 4.30/4.50 SZS status Theorem for theBenchmark.p % 4.30/4.50 SZS output start Proof for theBenchmark.p % 4.30/4.50 Clause #0 (by assumption #[]): Eq (Not (And (Iff a b) (cP a) → cP b)) True % 4.30/4.50 Clause #1 (by clausification #[0]): Eq (And (Iff a b) (cP a) → cP b) False % 4.30/4.50 Clause #2 (by clausification #[1]): Eq (And (Iff a b) (cP a)) True % 4.30/4.50 Clause #3 (by clausification #[1]): Eq (cP b) False % 4.30/4.50 Clause #4 (by clausification #[2]): Eq (cP a) True % 4.30/4.50 Clause #5 (by clausification #[2]): Eq (Iff a b) True % 4.30/4.50 Clause #6 (by identity loobHoist #[4]): Or (Eq (cP True) True) (Eq a False) % 4.30/4.50 Clause #7 (by identity boolHoist #[4]): Or (Eq (cP False) True) (Eq a True) % 4.30/4.50 Clause #8 (by identity loobHoist #[3]): Or (Eq (cP True) False) (Eq b False) % 4.30/4.50 Clause #9 (by identity boolHoist #[3]): Or (Eq (cP False) False) (Eq b True) % 4.30/4.50 Clause #10 (by clausification #[5]): Or (Eq a True) (Eq b False) % 4.30/4.50 Clause #11 (by clausification #[5]): Or (Eq a False) (Eq b True) % 4.30/4.50 Clause #12 (by superposition #[9, 7]): Or (Eq b True) (Or (Eq False True) (Eq a True)) % 4.30/4.50 Clause #13 (by clausification #[12]): Or (Eq b True) (Eq a True) % 4.30/4.50 Clause #14 (by superposition #[13, 10]): Or (Eq a True) (Or (Eq a True) (Eq True False)) % 4.30/4.50 Clause #15 (by clausification #[14]): Or (Eq a True) (Eq a True) % 4.30/4.50 Clause #16 (by eliminate duplicate literals #[15]): Eq a True % 4.30/4.50 Clause #17 (by backward demodulation #[16, 6]): Or (Eq (cP True) True) (Eq True False) % 4.30/4.50 Clause #19 (by backward demodulation #[16, 11]): Or (Eq True False) (Eq b True) % 4.30/4.50 Clause #22 (by clausification #[19]): Eq b True % 4.30/4.50 Clause #23 (by backward demodulation #[22, 8]): Or (Eq (cP True) False) (Eq True False) % 4.30/4.50 Clause #25 (by clausification #[17]): Eq (cP True) True % 4.30/4.50 Clause #26 (by clausification #[23]): Eq (cP True) False % 4.30/4.50 Clause #27 (by superposition #[26, 25]): Eq False True % 4.30/4.50 Clause #28 (by clausification #[27]): False % 4.30/4.50 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------