%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : TIM033_1 : TPTP v9.3.0. Released v9.3.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n001.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Tue May 5 07:16:13 PM UTC 2026 % Result : Theorem 3.34s 3.53s % Output : Proof 3.34s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.00/0.12 % Problem : TIM033_1 : TPTP v9.3.0. Released v9.3.0. % 0.12/0.13 % Command : duper %s % 0.17/0.34 % Computer : n001.cluster.edu % 0.17/0.34 % Model : x86_64 x86_64 % 0.17/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.17/0.34 % Memory : 8042.1875MB % 0.17/0.34 % OS : Linux 3.10.0-693.el7.x86_64 % 0.17/0.34 % CPULimit : 300 % 0.17/0.34 % WCLimit : 300 % 0.17/0.34 % DateTime : Mon May 4 18:35:03 EDT 2026 % 0.17/0.35 % CPUTime : % 3.34/3.53 SZS status Theorem for theBenchmark.p % 3.34/3.53 SZS output start Proof for theBenchmark.p % 3.34/3.53 Clause #5 (by assumption #[]): Eq (∀ (I J : interval), Iff (finishes I J) (finished_by J I)) True % 3.34/3.53 Clause #10 (by assumption #[]): Eq (finishes d c) True % 3.34/3.53 Clause #11 (by assumption #[]): Eq (Not (finished_by c d)) True % 3.34/3.53 Clause #12 (by clausification #[11]): Eq (finished_by c d) False % 3.34/3.53 Clause #24 (by clausification #[5]): ∀ (a : interval), Eq (∀ (J : interval), Iff (finishes a J) (finished_by J a)) True % 3.34/3.53 Clause #25 (by clausification #[24]): ∀ (a a_1 : interval), Eq (Iff (finishes a a_1) (finished_by a_1 a)) True % 3.34/3.53 Clause #27 (by clausification #[25]): ∀ (a a_1 : interval), Or (Eq (finishes a a_1) False) (Eq (finished_by a_1 a) True) % 3.34/3.53 Clause #28 (by superposition #[27, 10]): Or (Eq (finished_by c d) True) (Eq False True) % 3.34/3.53 Clause #29 (by clausification #[28]): Eq (finished_by c d) True % 3.34/3.53 Clause #30 (by superposition #[29, 12]): Eq True False % 3.34/3.53 Clause #36 (by clausification #[30]): False % 3.34/3.53 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------