%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : TIM035_1 : TPTP v9.3.0. Released v9.3.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n011.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Tue May 5 07:16:13 PM UTC 2026 % Result : Theorem 3.55s 3.71s % Output : Proof 3.55s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.00/0.12 % Problem : TIM035_1 : TPTP v9.3.0. Released v9.3.0. % 0.11/0.13 % Command : duper %s % 0.17/0.34 % Computer : n011.cluster.edu % 0.17/0.34 % Model : x86_64 x86_64 % 0.17/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.17/0.34 % Memory : 8042.1875MB % 0.17/0.34 % OS : Linux 3.10.0-693.el7.x86_64 % 0.17/0.34 % CPULimit : 300 % 0.17/0.34 % WCLimit : 300 % 0.17/0.34 % DateTime : Mon May 4 18:37:17 EDT 2026 % 0.17/0.34 % CPUTime : % 3.55/3.71 SZS status Theorem for theBenchmark.p % 3.55/3.71 SZS output start Proof for theBenchmark.p % 3.55/3.71 Clause #2 (by assumption #[]): Eq (∀ (I J : interval), Iff (overlaps I J) (overlapped_by J I)) True % 3.55/3.71 Clause #8 (by assumption #[]): Eq (overlaps a b) True % 3.55/3.71 Clause #11 (by assumption #[]): Eq (Not (overlapped_by b a)) True % 3.55/3.71 Clause #12 (by clausification #[11]): Eq (overlapped_by b a) False % 3.55/3.71 Clause #40 (by clausification #[2]): ∀ (a : interval), Eq (∀ (J : interval), Iff (overlaps a J) (overlapped_by J a)) True % 3.55/3.71 Clause #41 (by clausification #[40]): ∀ (a a_1 : interval), Eq (Iff (overlaps a a_1) (overlapped_by a_1 a)) True % 3.55/3.71 Clause #43 (by clausification #[41]): ∀ (a a_1 : interval), Or (Eq (overlaps a a_1) False) (Eq (overlapped_by a_1 a) True) % 3.55/3.71 Clause #46 (by superposition #[43, 8]): Or (Eq (overlapped_by b a) True) (Eq False True) % 3.55/3.71 Clause #47 (by clausification #[46]): Eq (overlapped_by b a) True % 3.55/3.71 Clause #48 (by superposition #[47, 12]): Eq True False % 3.55/3.71 Clause #50 (by clausification #[48]): False % 3.55/3.71 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------